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ZOJ 3621 Factorial Problem in Base K

2018年04月21日 ⁄ 综合 ⁄ 共 849字 ⁄ 字号 评论关闭

s! 在 K 进制下 最后有多少个0 

分解质因数

#include <cstdio>
#include <cstring>
#include <iostream>
using namespace std;
typedef long long  ll;
int const MAXN = 1000;
bool prime[MAXN];
char str[MAXN];
void Judge_Prime(){
    memset(prime,false,sizeof(prime));
    for(int i = 2;i < MAXN;i++){
        if(!prime[i]){
            for(int j = 2 * i;j < MAXN;j += i){
                prime[j] = true;
            }
        }
    }
}
ll Get_S(int k){
    int len = strlen(str);
    ll base = 1,sum = 0;
    for(int i = len - 1;i >= 0;i--){
        int a;
        if(str[i] >= 'A' && str[i] <= 'Z') a = str[i] - 'A' + 10;
        else if(str[i] >= 'a' && str[i] <= 'z') a = str[i] - 'a' + 36;
        else a = str[i] - '0';
        sum += a * base;
        base *= k;
    }
    return sum;
}
ll Calc(int i,ll s){
    ll ret = 0;
    ll base = i;
    while(s >= i){
        ret += s / i;
        s /= i;
    }
    return ret;
}
int main(){
    Judge_Prime();
    int k;
    while(~scanf("%s%d",str,&k)){
        ll s = Get_S(k);
        cout<<s<<endl;
        ll ret = -1;
        for(int i = 2;i <= k;i++){
            if(k % i == 0 && !prime[i]){
                int a = 0,temp = k;
                while(temp % i == 0){
                    a++;
                    temp /= i;
                }
                ll b = Calc(i,s);
                if(ret == -1 || ret > (b / a)) ret = b / a;
            }
        }
        cout<<ret<<endl;
    }
    return 0;
}
/*
F4 46
1111111 62


*/

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