注意输出进位次数超过1是要加s
小学生算术
#include <cstdio> #include <cstring> #include <iostream> using namespace std; char str1[12],str2[12]; int num1[12],num2[12]; int main(){ int a,b; while(~scanf("%d%d",&a,&b),(a || b)){ sprintf(str1,"%d",a); sprintf(str2,"%d",b); memset(num1,0,sizeof(num1)); memset(num2,0,sizeof(num2)); int sum = 0,count = 0; int l1 = strlen(str1),l2 = strlen(str2); for(int i = l1 - 1;i >= 0;i--){ num1[count++] = str1[i] - '0'; } count = 0; for(int i = l2 - 1;i >= 0;i--) num2[count++] = str2[i] - '0'; for(int i = 0;i < 12;i++){ num1[i] += num2[i]; if(num1[i] >= 10){ num1[i + 1] += 1; num1[i] -= 10; sum++; } } if(!sum)printf("No carry operation.\n"); else if(sum == 1)printf("%d carry operation.\n",sum); else printf("%d carry operations.\n",sum); } return 0; }
#include <cstdio> #include <cstring> #include <iostream> using namespace std; char str1[20],str2[20]; int num1[20],num2[20]; int main(){ while(cin>>str1>>str2){ memset(num1,0,sizeof(num1)); memset(num2,0,sizeof(num2)); int sum = 0,count = 0; int l1 = strlen(str1),l2 = strlen(str2); if(l1 == 1 && l2 == 1 && str1[0] == '0' && str2[0] == '0'){break;} for(int i = l1 - 1;i >= 0;i--){ num1[count++] = str1[i] - '0'; } count = 0; for(int i = l2 - 1;i >= 0;i--){ num2[count++] = str2[i] - '0'; } for(int i = 0;i < 19;i++){ num1[i] += num2[i]; if(num1[i] >= 10){ num1[i + 1] += num1[i] / 10; num1[i] %= 10; sum++; } } if(!sum)printf("No carry operation.\n"); else if(sum == 1) printf("%d carry operation.\n",sum); else printf("%d carry operations.\n",sum); } return 0;