还是字典树的基础题,纯粹为了熟练代码,加深理解
#include <set> #include <map> #include <ctime> #include <queue> #include <cmath> #include <stack> #include <limits> #include <vector> #include <bitset> #include <string> #include <cstdio> #include <cstring> #include <fstream> #include <string.h> #include <iostream> #include <algorithm> #define Si set<int> #define LL long long #define pb push_back #define PS printf(" ") #define Vi vector<int> #define LN printf("\n") #define lson l,m,rt << 1 #define rson m + 1,r,rt<<1|1 #define SD(a) scanf("%d",&(a)) #define PD(a) printf("%d\n",a) #define SET(a,b) memset(a,b,sizeof(a)) #define readf freopen("input.txt","r",stdin) #define writef freopen("output.txt","w",stdout) #define FF(i,a) for(int i(0);i<(a);i++) #define FD(i,a) for(int i(a);i>=(1);i--) #define FOR(i,a,b) for(int i(a);i<=(b);i++) #define FOD(i,a,b) for(int i(a);i>=(b);i--) const int maxn = 301; const int INF = ~0U>>1; const int dx[]={0,1,0,-1}; const int dy[]={1,0,-1,0}; const double pi = acos(-1.0); using namespace std; char a[1001][21]; class tire{ public: int pre; tire *next[26]; tire(){ pre=0; SET(next,0); } }root; void insert(char *word){ tire *p=&root; int k=0; while(word[k]!='\0'){ if(!p->next[word[k]-'a']) p->next[word[k]-'a']=new tire; p=p->next[word[k]-'a']; p->pre++; k++; } } void query(char *word){ tire *p=&root; int k=0; while(word[k]){ if(p->pre==1) return; printf("%c",word[k]); int t=word[k]-'a'; p=p->next[t]; k++; } } int main() { int cnt=0; while(~scanf("%s",a[cnt])){ insert(a[cnt]); cnt++; } FF(i,cnt){ printf("%s ",a[i]); query(a[i]); LN; } return 0; }