比较水的dfs题目
code:
/* ID: yueqiq LANG: C++ TASK: zerosum */ #include <set> #include <map> #include <ctime> #include <queue> #include <cmath> #include <stack> #include <limits> #include <vector> #include <bitset> #include <string> #include <cstdio> #include <cstring> #include <fstream> #include <string.h> #include <iostream> #include <algorithm> #define ls rt<<1 #define rs rt<<1|1 #define Si set<int> #define LL long long #define pb push_back #define PS printf(" ") #define Vi vector<int> #define LN printf("\n") #define SD(a) scanf("%d",&a) #define PD(a) printf("%d",a) #define SET(a,b) memset(a,b,sizeof(a)) #define FF(i,a) for(int i(0);i<(a);i++) #define FD(i,a) for(int i(a);i>=(1);i--) #define FOR(i,a,b) for(int i(a);i<=(b);i++) #define FOD(i,a,b) for(int i(a);i>=(b);i--) #define readf freopen("zerosum.in","r",stdin) #define writef freopen("zerosum.out","w",stdout) const double pi = acos(-1.0); const int maxn = 50; const int BigP = 99999999; const int INF = 99999999; const int dx[]={0,1,0,-1}; const int dy[]={1,0,-1,0}; using namespace std; int N; char str[20]; void dfs(int k,int sum,int last){ if(k==N){ if(sum+last==0) cout<<str<<endl; return ; } str[k*2-1]=' '; dfs(k+1,sum,last>0?last*10+k+1:last*10-k-1); str[k*2-1]='+'; dfs(k+1,sum+last,k+1); str[k*2-1]='-'; dfs(k+1,sum+last,-k-1); } int main (){ readf; writef; SD(N); FF(i,N) str[i*2]=char(i+'1'); dfs(1,0,1); return 0; }