此题真心没发现跟贪心有一点关系.........刚开始就想到了了取巧的办法,真心懒.........
code
#include <set> #include <map> #include <ctime> #include <queue> #include <cmath> #include <stack> #include <limits> #include <vector> #include <bitset> #include <string> #include <cstdio> #include <cstring> #include <fstream> #include <string.h> #include <iostream> #include <algorithm> #define Si set<int> #define LL long long #define pb push_back #define PS printf(" ") #define Vi vector<int> #define LN printf("\n") #define lson l,m,rt << 1 #define rson m+1,r,rt<<1|1 #define SD(a) scanf("%d",&a) #define PD(a) printf("%d\n",a) #define SET(a,b) memset(a,b,sizeof(a)) #define FF(i,a) for(int i(0);i<(a);i++) #define FD(i,a) for(int i(a);i>=(1);i--) #define FOR(i,a,b) for(int i(a);i<=(b);i++) #define FOD(i,a,b) for(int i(a);i>=(b);i--) #define readf freopen("input.txt","r",stdin) #define writef freopen("output.txt","w",stdout) const int maxn = 1006; const int INF = ~0U>>1; const int dx[]={0,1,0,-1}; const int dy[]={1,0,-1,0}; const double pi = acos(-1.0); using namespace std; int main() { double n,p; while(~scanf("%lf%lf",&n,&p)){ printf("%.f\n",pow(p,1.0/n)); } return 0; }
之后就想试一下二分怎么样,结果无限WA,求解!!!!!!!
一下是错误的code
import java.math.BigInteger; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner cin = new Scanner(System.in); while(cin.hasNext()){ int a=cin.nextInt(); BigInteger b=new BigInteger(cin.next()); if(a==1){ System.out.println(b); continue; } int l=1,r=Math.min(1000000000,b.intValue()); while(l<=r){ BigInteger mid=new BigInteger((l+r)/2+""); if(mid.pow(a).compareTo(b)==0){ System.out.println(mid); break; } else if(mid.pow(a).compareTo(b)<0) l=mid.intValue()+1; else{ r=mid.intValue(); } } } } }