Milking Cows
题意:给定一堆线段,求最长的不覆盖区间,和最长的覆盖区间
就是维护当前的一块线段,如果不是断开的,就把当前的线段包括进去,否则从当前线段开始
code
/* ID : Your ID LANG : C++ PROB : milk2 */ #include <set> #include <map> #include <ctime> #include <queue> #include <cmath> #include <stack> #include <limits> #include <vector> #include <bitset> #include <string> #include <cstdio> #include <cstring> #include <fstream> #include <string.h> #include <iostream> #include <algorithm> #define Si set<int> #define LL long long #define pb push_back #define PS printf(" ") #define Vi vector<int> #define LN printf("\n") #define lson l,m,rt << 1 #define rson m+1,r,rt<<1|1 #define SD(a) scanf("%d",&a) #define PD(a) printf("%d",a) #define SET(a,b) memset(a,b,sizeof(a)) #define FF(i,a) for(int i(0);i<(a);i++) #define FD(i,a) for(int i(a);i>=(1);i--) #define FOR(i,a,b) for(int i(a);i<=(b);i++) #define FOD(i,a,b) for(int i(a);i>=(b);i--) #define readf freopen("input.txt","r",stdin) #define writef freopen("output.txt","w",stdout) const int maxn = 1005; const int INF = 0xfffffff; const int dx[]={0,1,0,-1}; const int dy[]={1,0,-1,0}; const double pi = acos(-1.0); using namespace std; struct seg{ int st,ed; }a[5001]; bool cmp(const seg x,const seg y){ return x.st<y.st; } int N,ans1,ans2; int main() { freopen("milk2.in","r",stdin); freopen("milk2.out","w",stdout); SD(N); FOR(i,1,N){ SD(a[i].st); SD(a[i].ed); } sort(a+1,a+N+1,cmp); int left=a[1].st,right=a[1].ed; ans1=right-left; FOR(i,2,N){ if(a[i].st>right){ ans1=max(ans1,right-left); ans2=max(ans2,a[i].st-right); left=a[i].st; right=a[i].ed; }else right=max(a[i].ed,right); } printf("%d %d\n",ans1,ans2); return 0; }