直接模拟就能过,不过刚开始看错题了。。。。
code:
/* ID:yueqi LANG:C++ TASK:ttwo */ #include <set> #include <map> #include <ctime> #include <queue> #include <cmath> #include <stack> #include <limits.h> #include <vector> #include <bitset> #include <string> #include <cstdio> #include <cstring> #include <fstream> #include <string.h> #include <iostream> #include <algorithm> #define Si set<int> #define LL long long #define pb push_back #define PS printf(" ") #define Vi vector<int> #define LN printf("\n") #define lson l,m,rt << 1 #define rson m+1,r,rt<<1|1 #define SD(a) scanf("%d",&a) #define PD(a) printf("%d",a) #define SET(a,b) memset(a,b,sizeof(a)) #define FF(i,a) for(int i(0);i<(a);i++) #define FD(i,a) for(int i(a);i>=(1);i--) #define FOR(i,a,b) for(int i(a);i<=(b);i++) #define FOD(i,a,b) for(int i(a);i>=(b);i--) #define readf freopen("ttwo.in","r",stdin) #define writef freopen("ttwo.out","w",stdout) const int maxn = 101; const long long BigP=999983; const long long INF = 0x5fffffff; const int dx[]={-1,0,1,0}; const int dy[]={0,1,0,-1}; const double pi = acos(-1.0); const double eps= 1e-7; using namespace std; //注意dx,dy是按照顺时针的顺序排好的 int fstep,cstep; int fx,fy,cx,cy,fdir,cdir,ans; bool Map[12][12]; void read(){ char buf[20]; FOR(i,1,10){ scanf("%s",buf); FOR(j,1,10){ switch(buf[j-1]){ case '.': Map[i][j]=1;break; case '*': Map[i][j]=0;break; case 'F': fx=i;fy=j;Map[i][j]=1;break; case 'C': cx=i;cy=j;Map[i][j]=1;break; } } } } void move(int &x,int &y,int &dir){ if(Map[x+dx[dir]][y+dy[dir]]==1){ x+=dx[dir];y+=dy[dir]; }else dir=(dir+1)%4; } void solve(){ int ans=0; while(!(fx==cx&&fy==cy) && ans<100000){ //printf("stert fx:%d fy:%d cx:%d cy:%d\n",fx,fy,cx,cy); move(fx,fy,fdir); move(cx,cy,cdir); //printf("end fx:%d fy:%d cx:%d cy:%d\n",fx,fy,cx,cy); ans++; } if(ans!=100000){ PD(ans);LN; }else puts("0"); } int main(){ readf; writef; read(); solve(); return 0; }