主要思路就是求出序列的逆序数,此逆序数就是冒泡排序的交换次数
求逆序数采用归并排序,因为在每次归并排序中,如果左边大于右边,那么左边从此往后的数全部大于右边
code:
#include <set> #include <map> #include <ctime> #include <queue> #include <cmath> #include <stack> #include <limits> #include <vector> #include <bitset> #include <string> #include <cstdio> #include <cstring> #include <fstream> #include <string.h> #include <iostream> #include <algorithm> #define ls rt<<1 #define rs rt<<1|1 #define Si set<int> #define LL long long #define pb push_back #define PS printf(" ") #define Vi vector<int> #define LN printf("\n") #define SD(a) scanf("%d",&a) #define PD(a) printf("%d",a) #define SET(a,b) memset(a,b,sizeof(a)) #define FF(i,a) for(int i(0);i<(a);i++) #define FD(i,a) for(int i(a);i>=(1);i--) #define FOR(i,a,b) for(int i(a);i<=(b);i++) #define FOD(i,a,b) for(int i(a);i>=(b);i--) #define readf freopen("input.txt","r",stdin) #define writef freopen("output.txt","w",stdout) const int maxn = 500001; const int INF = 0x3fffffff; const int dx[]={0,1,0,-1}; const int dy[]={1,0,-1,0}; const double pi = acos(-1.0); using namespace std; int sr[maxn],tr[maxn]; __int64 cnt; void Merge(int r, int m, int t){ int k, j, i=r; for (j =m+1, k = i; i<=m && j <= t; ++k){ if (sr[i] > sr[j]){ tr[k] = sr[j++]; cnt += m-i+1; } else tr[k] = sr[i++]; } while (i<=m) tr[k++] = sr[i++]; while (j<=t) tr[k++] = sr[j++]; for (i=r; i<=t; ++i) sr[i] = tr[i]; }//Merge void MSort(int r, int t){ int m = (r + t)/2; if (r < t){ MSort(r, m); MSort(m+1, t); Merge(r, m, t); } }//MSort int main(){ int n; while (~scanf("%d", &n), n){ int i; FOR(i,1,n) SD(sr[i]); cnt = 0; MSort(1,n); printf("%I64d\n", cnt); } return 0; }