1 second
256 megabytes
standard input
standard output
Bizon the Champion is called the Champion for a reason.
Bizon the Champion has recently got a present — a new glass cupboard with n shelves and he decided to put all his presents there. All the presents can be
divided into two types: medals and cups. Bizon the Champion has a1 first
prize cups, a2 second
prize cups and a3third
prize cups. Besides, he has b1 first
prize medals, b2 second
prize medals and b3 third
prize medals.
Naturally, the rewards in the cupboard must look good, that's why Bizon the Champion decided to follow the rules:
- any shelf cannot contain both cups and medals at the same time;
- no shelf can contain more than five cups;
- no shelf can have more than ten medals.
Help Bizon the Champion find out if we can put all the rewards so that all the conditions are fulfilled.
The first line contains integers a1, a2 and a3 (0 ≤ a1, a2, a3 ≤ 100).
The second line contains integers b1, b2 and b3 (0 ≤ b1, b2, b3 ≤ 100).
The third line contains integer n (1 ≤ n ≤ 100).
The numbers in the lines are separated by single spaces.
Print "YES" (without the quotes) if all the rewards can be put on the shelves in the described manner. Otherwise, print "NO"
(without the quotes).
1 1 1 1 1 1 4
YES
1 1 3 2 3 4 2
YES
1 0 0 1 0 0 1
NO
额……好久没刷cf了
第一题模拟一下
#include<cstdio>
#define LL long long
using namespace std;
inline int read()
{
int x=0,f=1;char ch=getchar();
while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}
while(ch>='0'&&ch<='9'){x=x*10+ch-'0';ch=getchar();}
return x*f;
}
LL a,b,c,d,e,f,g,h,n;
int main()
{
scanf("%lld%lld%lld%lld%lld%lld",&a,&b,&c,&d,&e,&f);
g=a+b+c;
h=d+e+f;
scanf("%lld",&n);
if (g%5)n--;
if (h%10)n--;
if (g/5+h/10<=n) printf("YES");
else printf("NO");
return 0;
}