学步园

Suppose a sorted array is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4
5 6 7 0 1 2).

Find the minimum element.

You may assume no duplicate exists in the array.

class Solution {
public:
    int findMin(vector<int> &num) {
        int left = 0, right = num.size()-1;
        while(left < right)
        {
            int mid = left + (right - left) / 2;
            if(num[mid] < num[right])
                right = mid;
            else if(num[mid] > num[right])
                left = mid + 1;
        }
        return num[left];
    }
};