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Balanced Binary Tree

2018年04月29日 ⁄ 综合 ⁄ 共 954字 ⁄ 字号 评论关闭

仔细,仔细,仔细!

#include <iostream>
#include <algorithm>
#include <queue>

using namespace std;

struct TreeNode {
    int val;
    TreeNode *left;
    TreeNode *right;
    TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};

class Solution {
public:
	int getheight(TreeNode *p)
	{
		if(!p)
			return 0;
		else
			return 1 + max(getheight(p->left), getheight(p->right));
	}
	
    bool isBalanced(TreeNode *root) 
    {
    	if(!root)
    		return true;
    	q.push(root);
    	while(!q.empty())
    	{
	    	TreeNode *p = q.front();
			q.pop();
			
			if(abs(getheight(p->left) - getheight(p->right)) > 1)
				return false;
			else
			{
				if(p->left)
					q.push(p->left);
				if(p->right)
					q.push(p->right);
			}	
	    }
    	return true;	
    }
private:
	queue<TreeNode*> q;
};

int main(void)
{
	TreeNode *root = new TreeNode(0);
/*
	TreeNode *node1 = new TreeNode(1); root->left = node1;
	TreeNode *node2 = new TreeNode(2); root->right = node2;
	
	TreeNode *node3 = new TreeNode(3); node1->left = node3;
	TreeNode *node4 = new TreeNode(4); node1->left = node4;
	
	TreeNode *node5 = new TreeNode(5); node3->left = node5;
	TreeNode *node6 = new TreeNode(6); node4->right = node6;*/
	
	Solution s;
	
	cout << s.isBalanced(root) << endl;
	
	return 0;
}

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