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uvaoj-401-Palindromes

2018年05月04日 ⁄ 综合 ⁄ 共 1104字 ⁄ 字号 评论关闭

比较简单的题目,WA了一次是没看清英文题目的要求。

/*
    uvaoj:  401
    PROB:   Palindromes
*/
#include<stdio.h>
#include<string.h>
#define LOCAL
char st[25];
char reverse1[100] = "AEHIJLMOSTUVWXYZ12358";
char reverse2[100] = "A3HILJMO2TUVWXY51SEZ8";
int r;
int is_regular( char st[] );
int is_mirrored( char st[] );
int main()
{
    r = strlen(reverse1);
    #ifdef LOCAL
    freopen("Palindromes.in.txt", "r", stdin);
    freopen("Palindromes.out.txt", "w", stdout);
    #endif // LOCAL
    while( gets(st) != NULL )
    {

        int m, n;
        int len = strlen(st);
        m = is_regular(st);
        n = is_mirrored(st);
        if(m)
        {
            if(n)   printf("%s -- is a mirrored palindrome.\n", st);
            else    printf("%s -- is a regular palindrome.\n", st);
        }
        else
        {
            if(n)   printf("%s -- is a mirrored string.\n", st);
            else    printf("%s -- is not a palindrome.\n", st);
        }
        printf("\n");
    }
    return 0;
}
int is_regular( char st[] )
{
    int i, j, len, yes=1;
    char s[30];
    strcpy(s,st);
    len = strlen(s);
    for( i=0; i<len/2; i++ )
        if( s[i] != s[len-1-i] )
        {
            yes = 0;
            break;
        }
    return yes;
}
int is_mirrored( char st[] )
{
    int yes = 1;
    char s1[30], s2[30];
    strcpy(s1,st);
    strcpy(s2,st);
    int i, len, n;
    len = strlen(s1);
    for( i=0; i<len; i++ )
    {
        int found = 0;
        for(n=0; n<r; n++)
        {
            if(s1[i] == reverse1[n])
                { s1[i] = reverse2[n];   found = 1;   break;  }
        }
        if(!found)  return 0;
    }
    strcat(s2,s1);
    if( is_regular(s2) )
        return 1;
    else
        return 0;
}

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