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链表翻转的递归和非递归算法

2018年05月13日 ⁄ 综合 ⁄ 共 966字 ⁄ 字号 评论关闭

#include <iostream>

#include <stdio.h>
using namespace std;

template<typename T>
struct Node
{
    Node ( T value ) : mValue(value),mNext(0)
    {
    }
    Node *mNext;
    T mValue;
};

template<typename T>
Node<T> *recursiveReverse( Node<T> *currentNode )
{
    if (currentNode->mNext == NULL)
    {
        return currentNode;
    }
    else
    {
        Node<T>* tmp = recursiveReverse<T>(currentNode->mNext);
        currentNode->mNext->mNext = currentNode;
        currentNode->mNext =NULL;
        return tmp;
    }
}

template<typename T>
Node<T> *
noneRecursive( Node<T> * root )
{
    if ( 0 == root )
    {
        return 0;
    }
    Node<T> * retval = 0;
    while ( root )
    {
        Node<T> *nextNode = root->mNext;
        root->mNext = retval;
        retval = root;
        root = nextNode;
    }
    return retval ;
}

template<typename T>
void dump(Node<T> *head)
{
    while ( head )
    {
        cout << head->mValue<<" ";
        head = head->mNext;
    }
    cout << endl;
}

int main(int, char *[])
{
    Node<int> *head = new Node<int>(0);
    Node<int> *currentNode = head;
    for ( int i = 1 ; i < 10 ; i ++ )
    {
        Node<int> *tmp = new Node<int>(i);
        currentNode->mNext = tmp;
        currentNode = tmp;
    }
    Node<int> *result = recursiveReverse<int>(head);
    dump(result);
    head = noneRecursive<int>(result);
    dump(head);
    return 0;
}

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