在SQL Server 2005以上版本中,在一个增强的WaitFor命令,其作用可以和一个job相当。但使用更加简捷。
看MSDN:
http://msdn.microsoft.com/zh-cn/library/ms187331.aspx
语法为:
WAITFOR { DELAY 'time_to_pass' | TIME 'time_to_execute' | [ ( receive_statement ) | ( get_conversation_group_statement ) ] [ , TIMEOUT timeout ] }
以下示例在晚上 10:20 (22:20
) 执行存储过程 sp_update_job
。
USE msdb; EXECUTE sp_add_job @job_name = 'TestJob'; BEGIN WAITFOR TIME '22:20'; EXECUTE sp_update_job @job_name = 'TestJob', @new_name = 'UpdatedJob'; END; GO以下示例在两小时的延迟后执行存储过程。注意:Delay最多不超过24小时
BEGIN WAITFOR DELAY '02:00'; EXECUTE sp_helpdb; END; GO以下示例显示如何对
WAITFOR DELAY
选项使用局部变量。将创建一个存储过程,该过程将等待可变的时间段,然后将经过的小时、分钟和秒数信息返回给用户。
USE AdventureWorks2008R2; GO IF OBJECT_ID('dbo.TimeDelay_hh_mm_ss','P') IS NOT NULL DROP PROCEDURE dbo.TimeDelay_hh_mm_ss; GO CREATE PROCEDURE dbo.TimeDelay_hh_mm_ss ( @DelayLength char(8)= '00:00:00' ) AS DECLARE @ReturnInfo varchar(255) IF ISDATE('2000-01-01 ' + @DelayLength + '.000') = 0 BEGIN SELECT @ReturnInfo = 'Invalid time ' + @DelayLength + ',hh:mm:ss, submitted.'; -- This PRINT statement is for testing, not use in production. PRINT @ReturnInfo RETURN(1) END BEGIN WAITFOR DELAY @DelayLength SELECT @ReturnInfo = 'A total time of ' + @DelayLength + ', hh:mm:ss, has elapsed! Your time is up.' -- This PRINT statement is for testing, not use in production. PRINT @ReturnInfo; END; GO /* This statement executes the dbo.TimeDelay_hh_mm_ss procedure. */ EXEC TimeDelay_hh_mm_ss '00:00:10'; GO执行结果:
A total time of 00:00:10, in hh:mm:ss, has elapsed.Your time is up.小结:这是一种轻巧的解决方案。当你没有权限指定job时,可以考虑用WaitFor语句。