现在的位置: 首页 > 综合 > 正文

HDU 5151 Sit sit sit(区间DP)

2018年10月13日 ⁄ 综合 ⁄ 共 739字 ⁄ 字号 评论关闭

HDU 5151 Sit sit sit

题目链接

区间DP+组合计数问题,转移方程为,每次选当前区间最后一个放的位置,然后乘上组合数C[区间长度][左区间长度]

代码:

#include <cstdio>
#include <cstring>

typedef long long ll;

const ll MOD = 1000000007;

const int N = 105;

int n, a[N];
ll dp[N][N], C[N][N];

int main() {
    C[1][0] = C[1][1] = 1;
    for (int i = 2; i <= 100; i++) {
	C[i][0] = C[i][i] = 1;
	for (int j = 1; j < i; j++) {
	    C[i][j] = (C[i - 1][j] + C[i - 1][j - 1]) % MOD;
	}
    }
    while (~scanf("%d", &n)) {
	for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
	memset(dp, 0, sizeof(dp));
	for (int i = 1; i <= n; i++) dp[i][i] = 1;
	for (int len = 1; len < n; len++) {
	    for (int l = 1; l + len <= n; l++) {
		int r = l + len;
		for (int k = l; k <= r; k++) {
		    if (l == k) dp[l][r] = (dp[l][r] + dp[k + 1][r]) % MOD;
		    else if (r == k) dp[l][r] = (dp[l][r] + dp[l][k - 1]) % MOD;
		    else if (a[k - 1] == a[k + 1]) dp[l][r] = (dp[l][r] + (dp[l][k - 1] * dp[k + 1][r] % MOD * C[r - l][k - l]) % MOD) % MOD;
		}
	    }
	}
	printf("%lld\n", dp[1][n]);
    }
    return 0;
}

抱歉!评论已关闭.