Description
You have bought a car in order to drive from Waterloo to a big city. The odometer on their car is broken, so you cannot measure distance. But the speedometer and cruise control both work, so the car can maintain a constant speed which can be adjusted from time
to time in response to speed limits, traffic jams, and border queues. You have a stopwatch and note the elapsed time every time the speed changes. From time to time you wonder, "how far have I come?". To solve this problem you must write a program to run on
your laptop computer in the passenger seat.
to time in response to speed limits, traffic jams, and border queues. You have a stopwatch and note the elapsed time every time the speed changes. From time to time you wonder, "how far have I come?". To solve this problem you must write a program to run on
your laptop computer in the passenger seat.
Input
Standard input contains several lines of input: Each speed change is indicated by a line specifying the elapsed time since the beginning of the trip (hh:mm:ss), followed by the new speed in km/h. Each query is indicated by a line containing the elapsed time.
At the outset of the trip the car is stationary. Elapsed times are given in non-decreasing order and there is at most one speed change at any given time.
At the outset of the trip the car is stationary. Elapsed times are given in non-decreasing order and there is at most one speed change at any given time.
Output
For each query in standard input, you should print a line giving the time and the distance travelled, in the format below.
Sample Input
00:00:01 100 00:15:01 00:30:01 01:00:01 50 03:00:01 03:00:05 140
Sample Output
00:15:01 25.00 km 00:30:01 50.00 km 03:00:01 200.00 km
题目大意 很简单 ，但有几点需要注意 ： 第一 ，第一行 没有速度 要也要 输出 “0.00 km”； 第二 ，输入数据时 ，用 scanf或是 cin 会 RE ！！ 要用 gets（）~ 第三 ，这一点比较奇怪 ，我写的这个程序，用G++交能AC ，但用C++交 会 RE~ 具体讲解请看代码： #include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<string>
#include<cmath>
using namespace std;
int hh[100500],mm[100500],ss[100500];
char s[1000];
double speed[100500],lu[100500];
int main()
{
int i = 1,j;
memset(s,'\0',sizeof(s));
while (gets(s))
{
hh[i]=(s[0]-'0')*10 + (s[1]-'0');
mm[i]=(s[3]-'0')*10 + (s[4]-'0');
ss[i]=(s[6]-'0')*10 + (s[7]-'0');
lu[1] = 0;
int sumt;
if(s[8]==' ')
{
int l = strlen(s);
int k;
speed[i]=0;
for(k=9;k<l;k++)
{
speed[i]*=10;
speed[i]+=(s[k]-'0');
}
if(i > 1)
{
sumt = (hh[i]-hh[i-1])*3600 + (mm[i]-mm[i-1])*60 + (ss[i]-ss[i-1]);
lu[i] = sumt * speed[j]/3.6 + lu[i-1];
}
j=i;
i++;
memset(s,'\0',sizeof(s));
continue;
}
else
{
if(i > 1)
{
sumt = (hh[i]-hh[i-1])*3600 + (mm[i]-mm[i-1])*60 + (ss[i]-ss[i-1]);
lu[i] = sumt * speed[j]/3.6 + lu[i-1];
printf("%02d:%02d:%02d %.2f km\n",hh[i],mm[i],ss[i],lu[i]/1000);
}
else
printf("%02d:%02d:%02d %.2f km\n",hh[i],mm[i],ss[i],lu[i]/1000);
memset(s,'\0',sizeof(s));
i++;
}
}
return 0;
}