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递增数列中找和为s乘积最小的两个数

2019年02月10日 ⁄ 综合 ⁄ 共 561字 ⁄ 字号 评论关闭
#include<cstdio>

void getSumKPair(int *arr, int n, int k, int &a, int &b)
{
    int nLow, nHigh;
    long long product;
    nLow = 0, nHigh = n-1;
    a = b = -1, product = 0x7fffffff;
    int flag=0;
    while(nLow < nHigh)
    {
        if(arr[nLow] + arr[nHigh] == k )
        {
            if(!flag){
            a = nLow;
            b = nHigh;
            product = arr[a] * arr[b];
            ++nLow, --nHigh;
        }
        else if(arr[nLow] + arr[nHigh] < k)
            ++nLow;
        else
            --nHigh;
    }
}

const int MAX = 1000005;
int arr[MAX];
int main()
{
    int n, k, a, b;
    while(scanf("%d %d", &n, &k) != EOF)
    {
        for(a = 0; a < n; ++a)
            scanf("%d", &arr[a]);
        getSumKPair(arr, n, k, a, b);
        if(a == -1)
            puts("-1 -1");
        else
        {
            a = arr[a];
            b = arr[b];
            if(a > b)
                printf("%d %d\n", b, a);
            else
                printf("%d %d\n", a, b);
        }
    }
    return 0;
}

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