学步园

样例如图，加上各个集合的和就好了，然后每次集合都是剔除最小值得到新集合的

#include<stdio.h>
#include<string.h>
#include<queue>
#include<algorithm>
using namespace std;

#define rep(a, b) for(int i = (a); i <= (b); i++)
#define rev(a, b, i) for(int i = (a); i >= (b); i--)
#define FOR(a, b, i) for(int i = (a); i < (b); i++)

typedef long long LL;

int n;
int a;

struct cmp1{  
    bool operator ()(int &a,int &b){  
        return a>b;//最小值优先  
    }  
};

priority_queue<int, vector<int>, cmp1>q;//最小值优先  

//priority_queue<int, vector<int>, greater<int> >q;

LL ans, sum;

void init()
{
	while(!q.empty())
		q.pop();
	ans = 0, sum = 0;
}

void solve()
{
	rep(1, n)
	{
		scanf("%d", &a);
		q.push(a);
		sum += a;
	}
	ans = sum;
	int x;
	while(!q.empty())
	{
		x = q.top();
		ans += x;
		sum -= x;
		ans += sum;
		//printf("%d  ", ans);
		q.pop();
	}
	//puts("");
	printf("%lld\n", ans - x);
}


int main()
{
	while(~scanf("%d", &n))
	{
		init();
		solve();
	}
	return 0;
}