现在的位置: 首页 > 综合 > 正文

HDU 3523 Image copy detection & POJ 2516

2019年04月06日 ⁄ 综合 ⁄ 共 3562字 ⁄ 字号 评论关闭

2道KM。HDU 3523题目长了点,POJ 2516 需要拆点来做KM。

/*HDU 3523*/
#include <iostream>
#include <cstdlib>
#include <cstdio>
#include <string>
#include <cstring>
#include <cmath>
#include <vector>
#include <queue>
#include <algorithm>
#include <map>
#include <cctype>
using namespace std;

const int maxn = 110;
const int INF = 0x3f3f3f3f;

int n, m;

int W[maxn][maxn];
int Lx[maxn], Ly[maxn];

int Left[maxn];
bool S[maxn], T[maxn];

bool match(int i)
{
    S[i] = 1;
    for(int j = 1; j <= m; j++) if(Lx[i]+Ly[j] == W[i][j] && !T[j])
    {
        T[j] = 1;
        if(!Left[j] || match(Left[j]))
        {
            Left[j] = i;
            return 1;
        }
    }
    return 0;
}

void update()
{
    int a = INF;
    for(int i = 1; i <= n; i++) if(S[i])
    for(int j = 1; j <= m; j++) if(!T[j])
        a = min(a, Lx[i]+Ly[j]-W[i][j]);
        
    for(int i = 1; i <= n; i++)
    {
        if(S[i]) Lx[i] -= a;
    }
    for(int j = 1; j <= m; j++)
    {
        if(T[j]) Ly[j] += a;
    }
}

void KM()
{
    memset(Left, 0, sizeof(Left));
    memset(Lx, 0, sizeof(Lx));
    memset(Ly, 0, sizeof(Ly));
    
    for(int i = 1; i <= n; i++)
    {
        for(int j = 1; j <= m; j++)
            Lx[i] = max(Lx[i], W[i][j]);
    }
    for(int i = 1; i <= n; i++)
    {
        for(;;)
        {
            for(int j = 1; j <= m; j++) S[j] = T[j] = 0;
            if(match(i)) break; else update();
        }
    }
}

inline void readint(int &x)
{
    char c;
    c = getchar();
    while(!isdigit(c)) c = getchar();
    
    x = 0;
    while(isdigit(c)) x = x*10+c-'0', c = getchar();
}

inline void writeint(int x)
{
    if(x > 9) writeint(x/10);
    putchar(x%10+'0');
}

int N, M;

int Q[maxn][maxn];

void read_case()
{
	readint(N), readint(M);
	n = m = N;
	
	for(int i = 1; i <= M; i++)
	for(int j = 1; j <= N; j++) readint(Q[i][j]);
	
	for(int i = 1; i <= N; i++)
	{
		for(int j = 1; j <= N; j++)
		{
			W[i][j] = 0;
			for(int k = 1; k <= M; k++)
			{
				W[i][j] += -abs(Q[k][i]-j);
			}
		}
	}
}

int times;

void solve()
{
	read_case();
	
	KM();
	
	int ans = 0;
	for(int i = 1; i <= m; i++) if(Left[i]) ans -= W[Left[i]][i];
	printf("Case #%d: ", ++times);
	writeint(ans), puts("");
}

int main()
{
	int T;
	times = 0;
	for(readint(T); T > 0; T--)
	{
		solve();
	}
	return 0;
}

/*POJ 2516*/
#include <iostream>
#include <cstdlib>
#include <cstdio>
#include <string>
#include <cstring>
#include <cmath>
#include <vector>
#include <queue>
#include <algorithm>
#include <map>
#include <cctype>
using namespace std;

const int maxn = 210;
const int INF = 0x3f3f3f3f;

int n, m;

int W[maxn][maxn];
int Lx[maxn], Ly[maxn];

int Left[maxn];
bool S[maxn], T[maxn];

bool match(int i)
{
    S[i] = 1;
    for(int j = 1; j <= m; j++) if(Lx[i]+Ly[j] == W[i][j] && !T[j])
    {
        T[j] = 1;
        if(!Left[j] || match(Left[j]))
        {
            Left[j] = i;
            return 1;
        }
    }
    return 0;
}

void update()
{
    int a = INF;
    for(int i = 1; i <= n; i++) if(S[i])
    for(int j = 1; j <= m; j++) if(!T[j])
        a = min(a, Lx[i]+Ly[j]-W[i][j]);
        
    for(int i = 1; i <= n; i++)
    {
        if(S[i]) Lx[i] -= a;
    }
    for(int j = 1; j <= m; j++)
    {
        if(T[j]) Ly[j] += a;
    }
}

void KM()
{
    memset(Left, 0, sizeof(Left));
    memset(Lx, 0, sizeof(Lx));
    memset(Ly, 0, sizeof(Ly));
    
    for(int i = 1; i <= n; i++)
    {
        for(int j = 1; j <= m; j++)
            Lx[i] = max(Lx[i], W[i][j]);
    }
    for(int i = 1; i <= n; i++)
    {
        for(;;)
        {
            for(int j = 1; j <= m; j++) S[j] = T[j] = 0;
            if(match(i)) break; else update();
        }
    }
}

inline void readint(int &x)
{
    char c;
    c = getchar();
    while(!isdigit(c)) c = getchar();
    
    x = 0;
    while(isdigit(c)) x = x*10+c-'0', c = getchar();
}

inline void writeint(int x)
{
    if(x > 9) writeint(x/10);
    putchar(x%10+'0');
}

int buy[maxn][maxn];
int sale[maxn][maxn];
int cost[maxn][maxn][maxn];

int N, M, K;

void read_case()
{
	for(int i = 1; i <= N; i++)
	for(int j = 1; j <= K; j++) readint(buy[i][j]);
	
	for(int i = 1; i <= M; i++)
	for(int j = 1; j <= K; j++) readint(sale[i][j]);
	
	for(int k = 1; k <= K; k++)
	for(int i = 1; i <= N; i++)
	for(int j = 1; j <= M; j++) readint(cost[k][i][j]);
}

int check()
{
	for(int k = 1; k <= K; k++)
	{
		int t1 = 0, t2 = 0;
		for(int i = 1; i <= M; i++) t1 += sale[i][k];
		
		for(int i = 1; i <= N; i++) t2 += buy[i][k];
		if(t1 < t2) return -1;
	}
	return 1;
}

int A[maxn], B[maxn];

void solve()
{
	read_case();
	if(check() < 0) { printf("-1\n"); return ; }
	
	int ans = 0;
	for(int k = 1; k <= K; k++)
	{
		n = m = 1;
		
		for(int i = 1; i <= N; i++)
		for(int j = 1; j <= buy[i][k]; j++) A[n++] = i;
		
		for(int i = 1; i <= M; i++)
		for(int j = 1; j <= sale[i][k]; j++) B[m++] = i;
		
		n--, m--;
		memset(W, -INF, sizeof(W));
		for(int i = 1; i <= n; i++)
		for(int j = 1; j <= m; j++) W[i][j] = -cost[k][A[i]][B[j]];
		
		KM();
		
		for(int i = 1; i <= m; i++) if(Left[i]) ans -= W[Left[i]][i];
	}
	printf("%d\n", ans);
}

int main()
{
	while(~scanf("%d%d%d", &N, &M, &K) && (N || M || K))
	{
		solve();
	}
	return 0;
}

抱歉!评论已关闭.