最大费用圈覆盖,转换成图的匹配来解之。
/*HDU 3722*/ #include <iostream> #include <cstdlib> #include <cstdio> #include <string> #include <cstring> #include <cmath> #include <vector> #include <queue> #include <algorithm> #include <map> #include <cctype> using namespace std; const int maxn = 210; const int INF = 0x3f3f3f3f; int n, m; int W[maxn][maxn]; int Lx[maxn], Ly[maxn]; int Left[maxn]; bool S[maxn], T[maxn]; bool match(int i) { S[i] = 1; for(int j = 1; j <= m; j++) if(Lx[i]+Ly[j] == W[i][j] && !T[j]) { T[j] = 1; if(!Left[j] || match(Left[j])) { Left[j] = i; return 1; } } return 0; } void update() { int a = INF; for(int i = 1; i <= n; i++) if(S[i]) for(int j = 1; j <= m; j++) if(!T[j]) a = min(a, Lx[i]+Ly[j]-W[i][j]); for(int i = 1; i <= n; i++) { if(S[i]) Lx[i] -= a; } for(int j = 1; j <= m; j++) { if(T[j]) Ly[j] += a; } } void KM() { memset(Left, 0, sizeof(Left)); memset(Lx, 0, sizeof(Lx)); memset(Ly, 0, sizeof(Ly)); for(int i = 1; i <= n; i++) { for(int j = 1; j <= m; j++) Lx[i] = max(Lx[i], W[i][j]); } for(int i = 1; i <= n; i++) { for(;;) { for(int j = 1; j <= m; j++) S[j] = T[j] = 0; if(match(i)) break; else update(); } } } inline void readint(int &x) { char c; c = getchar(); while(!isdigit(c)) c = getchar(); x = 0; while(isdigit(c)) x = x*10+c-'0', c = getchar(); } inline void writeint(int x) { if(x > 9) writeint(x/10); putchar(x%10+'0'); } char str[210][1010]; void read_case() { char buf[1010]; m = n; for(int i = 1; i <= n; i++) scanf("%s", str[i]); } int cal(char *fir, char *sec) { int len1 = strlen(fir), len2 = strlen(sec); int i, j; for(i = len1-1, j = 0; i >= 0 && j < len2; i--, j++) { if(fir[i] != sec[j]) break; } return j; } void build() { for(int i = 1; i <= n; i++) { for(int j = 1; j <= n; j++) { W[i][j] = cal(str[i], str[j]); } W[i][i] = 0; } } void solve() { read_case(); build(); KM(); int ans = 0; for(int i = 1; i <= m; i++) if(Left[i]) ans += W[Left[i]][i]; printf("%d\n", ans); } int main() { while(~scanf("%d", &n)) { solve(); } return 0; }