大意略。
简单的三维空间判三角形相交。
#include <iostream> #include <cstdlib> #include <cstdio> #include <string> #include <cstring> #include <cmath> #include <vector> #include <queue> #include <stack> #include <algorithm> using namespace std; struct Point3 { double x, y, z; Point3(double x=0, double y=0, double z=0): x(x), y(y), z(z) {}; }; const double eps = 1e-8; typedef Point3 Vector3; int dcmp(double x) { if(fabs(x) < eps) return 0; else return x < 0 ? -1 : 1; } Vector3 operator + (const Vector3& A, const Vector3& B) { return Vector3(A.x+B.x, A.y+B.y, A.z+B.z); } Vector3 operator - (const Point3& A, const Point3& B) { return Vector3(A.x-B.x, A.y-B.y, A.z-B.z); } Vector3 operator * (const Vector3& A, double p) { return Vector3(A.x*p, A.y*p, A.z*p); } Vector3 operator / (const Vector3& A, double p) { return Vector3(A.x/p, A.y/p, A.z/p); } bool operator == (const Point3 &a, const Point3 &b) { return dcmp(a.x-b.x) == 0 && dcmp(a.y-b.y) == 0 && dcmp(a.z-b.z) == 0; } double Dot(Vector3 A, Vector3 B) { return A.x*B.x + A.y*B.y + A.z*B.z; } double Length(Vector3 A) { return sqrt(Dot(A, A)); } double Angle(Vector3 A, Vector3 B) { return acos(Dot(A, B) / Length(A) / Length(B)); } Vector3 Cross(Vector3 A, Vector3 B) { return Vector3(A.y*B.z - A.z*B.y, A.z*B.x - A.x*B.z, A.x*B.y - A.y*B.x); } double Area2(Point3 A, Point3 B, Point3 C) { return Length(Cross(B-A, C-A)); } bool PointInTri(Point3 P, Point3 P0, Point3 P1, Point3 P2) { double area1 = Area2(P, P0, P1); double area2 = Area2(P, P1, P2); double area3 = Area2(P, P2, P0); return dcmp(area1 + area2 + area3 - Area2(P0, P1, P2)) == 0; } bool TriSegIntersection(Point3 P0, Point3 P1, Point3 P2, Point3 A, Point3 B, Point3 &P) { Vector3 n = Cross(P1-P0, P2-P0); if(dcmp(Dot(n, B-A)) == 0) return false; else { double t = Dot(n, P0-A) / Dot(n, B-A); if(dcmp(t) < 0 || dcmp(t-1) > 0) return false; P = A + (B-A)*t; return PointInTri(P, P0, P1, P2); } } bool TriTriIntersection(Point3 *T1, Point3 *T2) { Point3 P; for(int i = 0; i < 3; i++) { if(TriSegIntersection(T1[0], T1[1], T1[2], T2[i], T2[(i+1)%3], P)) return true; if(TriSegIntersection(T2[0], T2[1], T2[2], T1[i], T1[(i+1)%3], P)) return true; } return false; } Point3 read_point3() { Point3 A; scanf("%lf%lf%lf", &A.x, &A.y, &A.z); return A; } Point3 T1[3], T2[3]; void solve() { for(int i = 0; i < 3; i++) T1[i] = read_point3(); for(int i = 0; i < 3; i++) T2[i] = read_point3(); if(TriTriIntersection(T1, T2)) printf("1\n"); else printf("0\n"); } int main() { int T; scanf("%d", &T); while(T--) { solve(); } return 0; }