大意不再赘述。
思路:练习高精度,注意去前导0。
#include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> #include <string> #include <algorithm> using namespace std; const int MAXN = 1010; char str1[MAXN], str2[MAXN]; char ope; struct bign { int len, s[MAXN]; bign () { memset(s, 0, sizeof(s)); len = 1; } bign (int num) { *this = num;} bign (const char *num) {*this = num;} void clean() { while(len > 1 && !s[len-1]) len--; } bign operator = (const char *num) { for(int i = 0; num[i] == '0'; num++) ; //去前导0 len = strlen(num); for(int i = 0; i < len; i++) s[i] = num[len-i-1] - '0'; return *this; } bign operator = (int num) { char s[MAXN]; sprintf(s, "%d", num); *this = s; return *this; } bool operator < (const bign &b) { if(len != b.len) return len < b.len; for(int i = len-1; i >= 0; i--) { if(s[i] != b.s[i]) return s[i] < b.s[i]; } return false; } bool operator >= (const bign &b) { return !(*this < b); } bign operator * (const bign &b) const { bign c; c.len = len + b.len; for(int i = 0; i < len; i++) { for(int j = 0; j < b.len; j++) { c.s[i+j] += s[i] * b.s[j]; } } for(int i = 0; i < c.len; i++) { c.s[i+1] += c.s[i] / 10; c.s[i] %= 10; } c.clean(); return c; } bign operator - (const bign &b) const { bign c; c.len = 0; for(int i = 0, g = 0; i < len; i++) { int x = s[i]-g; if(i < b.len) x -= b.s[i]; if(x >= 0) g = 0; else { g = 1; x += 10; } c.s[c.len++] = x; } c.clean(); return c; } bign operator / (const bign &b) const { bign c, f; for(int i = len-1; i >= 0; i--) { f = f*10; f.s[0] = s[i]; while(f >= b) { f = f-b; c.s[i]++; } } c.len = len; c.clean(); return c; } bign operator % (const bign &b) const { bign r = *this / b; r = *this - r*b; return r; } string str() const { string res = ""; for(int i = 0; i < len; i++) res = char(s[i]+'0')+res; if(res == "") res = "0"; return res; } }; istream& operator >> (istream &in, bign &x) { string s; in >> s; x = s.c_str(); return in; } ostream& operator << (ostream &out, const bign &x) { out << x.str(); return out; } int main() { bign a, b, ans; while(~scanf("%s %c %s", str1, &ope, str2)) { a = str1, b = str2; if(ope == '/') ans = a/b; if(ope == '%') ans = a%b; cout<<ans<<endl; } return 0; }