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android 发送一个http请求的问题

2019年09月12日 移动开发 ⁄ 共 2155字 ⁄ 字号 评论关闭

我是个新手,目前想在android app中发起一个简单的http请求,该请求到一个php页面左的网页上取一些数据,有没有可以通过后台运行去网站取数据并解析的功能?

第一步,把下面的代码加入到你的 manifest 文件中,目的是放开网络访问权限
<uses-permission android:name="android.permission.INTERNET" />

然后就可以使用 Apache http client 访问页面了,在android中非常的简单就能完成

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HttpClient
httpclient =
new

DefaultHttpClient();
    HttpResponse
response = httpclient.execute(
new

HttpGet(URL));
    StatusLine
statusLine = response.getStatusLine();
    if(statusLine.getStatusCode()
== HttpStatus.SC_OK){
        ByteArrayOutputStream
out =
new

ByteArrayOutputStream();
        response.getEntity().writeTo(out);
        out.close();
        String
responseString = out.toString();
        //..more
logic
    }
else{
        //Closes
the connection.
        response.getEntity().getContent().close();
        throw

new

IOException(statusLine.getReasonPhrase());
    }

如果你想在后台访问或者异步的方式运行,需要继承 AsyncTask,AsyncTask是专门单独线程跑后台任务的类

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class

RequestTask
extends

AsyncTask<string, string=
""

string,=
"">{
 
    @Override
    protected

String doInBackground(String... uri) {
        HttpClient
httpclient =
new

DefaultHttpClient();
        HttpResponse
response;
        String
responseString =
null;
        try

{
            response
= httpclient.execute(
new

HttpGet(uri[
0]));
            StatusLine
statusLine = response.getStatusLine();
            if(statusLine.getStatusCode()
== HttpStatus.SC_OK){
                ByteArrayOutputStream
out =
new

ByteArrayOutputStream();
                response.getEntity().writeTo(out);
                out.close();
                responseString
= out.toString();
            }
else{
                //Closes
the connection.
                response.getEntity().getContent().close();
                throw

new

IOException(statusLine.getReasonPhrase());
            }
        }
catch

(ClientProtocolException e) {
            //TODO
Handle problems..
        }
catch

(IOException e) {
            //TODO
Handle problems..
        }
        return

responseString;
    }
 
    @Override
    protected

void

onPostExecute(String result) {
        super.onPostExecute(result);
        //Do
anything with response..
    }
}</string,>

最后你可以通过如下的方式调用

new RequestTask().execute("http://stackoverflow.com");

原文地址:http://www.itmmd.com/201410/91.html

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