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栈的数组实现和链式实现

2012年04月15日 ⁄ 综合 ⁄ 共 2808字 ⁄ 字号 评论关闭

1,堆栈ADT

StackADT

package Stack;

public interface StackADT {

public void push(Object element);//压栈

public Object pop();//出栈

public boolean isEmpty();

public int size();

public Object peek();//返回栈顶对象的一个引用

public String toString();
}

2,链式实现

在栈的一段添加和删除元素,在栈中维护一个指向栈顶的结点和一个count变量指示栈的大小:

private LinearNode top; //指向栈顶
private int count;//标记栈的大小

每次出栈和压栈在链表的表头:(也可以再表尾,实现方式不一样而已)

top--->元素1--->元素2--->元素3.........

实现(附带测试main):

LinkedStack

package Stack;

import Bag.LinearNode;

//为了重点来实现算法,将异常情况直接打印出然后退出程序,不再声明异常类

public class LinkedStack implements StackADT {

private LinearNode top; //指向栈顶
private int count;//标记栈的大小

public static void main(String[] args){
LinkedStack stack
= new LinkedStack();

System.out.println(
"将0到10依次压栈");
for(int i = 0;i < 10;i++)
stack.push(i);
System.out.println(
"连续执行5次出栈操作");
for(int i = 0;i < 5;i++)
stack.pop();

System.out.println(
"栈为空吗?: " + stack.isEmpty());
System.out.println(
"栈的大小为: " + stack.size());
System.out.println(
"栈顶元素为: " + stack.top.getElement());
System.out.println(
"栈顶元素为: " + stack.peek());
}

public LinkedStack()
{
top
= null;
count
= 0;
}

public int size() {
return count;
}

public boolean isEmpty() {
return (size() == 0);
}

public void push(Object element) {
LinearNode node
= new LinearNode(element);
node.setNext(top);
top
= node;
count
++;
}

public Object pop() {
if(isEmpty())
{
System.out.println(
"stack is empty!");
System.exit(
1);
}
Object result
= top.getElement();
top
= top.getNext();
count
--;

return result;
}

public Object peek() {

Object result
= top.getElement();
return result;
}

}

运行结果:

将0到10依次压栈
连续执行5次出栈操作
栈为空吗?: false
栈的大小为: 5
栈顶元素为: 4
栈顶元素为: 4

3,数组实现

栈底总是数组下标为0的位置,入栈出栈从数组下标的最后一个元素开始:

private Object[] contents;
private int top;//top标记下一个入栈的位置,同时也表示栈的容量大小,跟链式实现的count比较一下!!!

实现(附带测试main):

ArrayStack

package Stack;

public class ArrayStack implements StackADT {

private Object[] contents;
private int top;//top标记下一个入栈的位置,同时也表示栈的容量大小,跟链式实现的count比较一下!!!

private static int SIZE = 10;


public ArrayStack()
{
contents
= new Object[SIZE];
top
= 0;
}

public void expand(){//借助于申请一个辅助空间,每次扩展容量一倍
Object[] larger = new Object[size()*2];
for(int index = 0;index < top;index++)
larger[index]
= contents[index];

contents
= larger;
}

public int size() {
return top;
}

public boolean isEmpty() {
return (size() == 0);
}

public void push(Object element) {
//if(isEmpty())
//expand();
if(top == contents.length)
expand();
contents[top]
= element;
top
++;
}

public Object pop() {
if(isEmpty())
{
System.out.println(
"stack is empty!");
System.exit(
1);
}

Object result
= contents[top-1];
contents[top
-1] = null;//出栈
top--;

return result;

/*书上这样写简便一点:::
* top--;
* Object result = contents[top];
* contents[top] = null;
*/
}

public Object peek() {
Object result;
if(isEmpty())
result
= null;
else
result
= contents[top-1];
return result;
}

public static void main(String[] args) {
ArrayStack stack
= new ArrayStack();
System.out.println(
"将0到24依次压栈,然后连续10次出栈");
for(int i = 0;i < 25;i++)
stack.push(i);
for(int i = 0;i < 10;i++)
stack.pop();
System.out.println(
"栈的大小为: " + stack.size());
System.out.println(
"栈为空吗?: " + stack.isEmpty());
System.out.println(
"栈顶元素为: " + stack.peek());
}


}

运行结果:

将0到24依次压栈,然后连续10次出栈
栈的大小为: 15
栈为空吗?: false
栈顶元素为: 14

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