学步园

最近做的东西涉及到从读取char数组中存放的十六进制数，每个char数据的码型（ASCII,BCD,FLOAT,HEX）不一样。需要进行对应数据类型的转换。实现如下：

string DataTrans::Char2BCD(unsigned char *c,int len)
{
       
       char s[100];
       char c1,c2;
       string str="";
       for(int i=0;i<len;i++)
       {
       	c1= c[i]&0x0f;
     	c2= c[i]>>4;
       int n=(int)(((c2&0x08+c2&0x04+c2&0x02+c2&0x01)<<4)+(c1&0x08+c1&0x04+c1&0x02+c1&0x01));
       if(n<=9&&n>=0)
       {
         str+="0";
       }
       str+=itoa(n,s,10);
       }
       return str;
}

void  DataTrans::Char2BYTE(unsigned char c, unsigned char *s)
{
     for(int i=7;i>=0;i--)
     {
          s[i]=c&0x01;
          c = c>>1;
     }   
}

float DataTrans::Char2Float(unsigned char *cp)
{
      return *(float *)cp;
}

string DataTrans::Char2Hex(char a1)
{
    string str = "";
    //int n = (a1<<8)+a2;
	int n=a1;
    for (int i=2*sizeof(char) - 1; i>=0; i--)
    {
        str += "0123456789ABCDEF"[((n >> i*4) & 0xF)];
    }
    return str;
}

int  DataTrans::Hex2Oct(unsigned  char c1, unsigned  char c2)
{
return (int)(c1<<8)+(int)c2;
}