我算了下，此时间会发生在北京时间2009年2月14日 07:30:30
程序如下
int main()
{
time_t now;
time(&now);
long diff = 1234567890 - now;
cout << "current: " << now << endl;
cout << "before 1234567890 we have:" << endl;
cout << diff << " secs"<< endl;
cout << diff / 60.0 << " minutes" << endl;
cout << diff / 3600.0 << " hours" << endl;
cout << endl;
long lnow = 1234567890;
tm* tnow;
tnow = localtime(&lnow);
cout << tnow->tm_year + 1900 << "-" << tnow->tm_mon + 1 << "-" << tnow->tm_mday << " " << tnow->tm_hour << ":" << tnow->tm_min << ":" << tnow->tm_sec;
return 0;
}
Unix weenies everywhere will be partying like it’s 1234567890 this Friday.
That’s because, at precisely 3:31:30 p.m. Pacific time on February
13, 2009, the 10-digit “epoch time” clock used by most Unix computers
will display all ten decimal digits in sequence. (That’s 6:31:30
Eastern, or 23:31:30 UTC.)
Unlike time systems intended for humans, Unix time
simply counts the number of seconds since midnight UTC on January 1,
1970. It’s a convenient way for computers to measure elapsed time,
provided the start date wasn’t before 1970. On Friday, the number of
seconds will hit 1,234,567,890. Celebrations
are planned in San Francisco, Vancouver, Seattle, Los Angeles and about
10 other locations worldwide, so don’t be surprised if it takes the
guys in IT a little longer to respond to your calls tomorrow afternoon,
or if the Gadget Lab crew is hard to find.
We couldn’t find any watches that display Unix time, but the above desk clock from ThinkGeek,
will do the trick. It will also display the time in binary, octal,
hexadecimal or Roman formats. Mark your calendars: It’s only 11 and a
half years until XX:XX:XX X/XX/XX day.
