<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE hibernate-mapping
PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"
> <hibernate-mapping><class name="onlyfun.caterpillar.User" table="user">
<composite-id>
<key-property name="name"
column
="name"type
="java.lang.String"/><key-property name="sex"
column
="sex"type
="java.lang.String"/></composite-id>
</class> </hibernate-mapping>
并且定义的User类要覆盖equals和hashCode方法
- Java code
-
public boolean equals(Object obj) { if(obj == this) { return true; } if(!(obj instanceof User)) { return false; } User user = (User) obj; return new EqualsBuilder() .append(this.name, user.getName()) .append(this.sex, user.getSex()) .isEquals(); } public int hashCode() { return new HashCodeBuilder() .append(this.name) .append(this.sex) .toHashCode(); }