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SQL2005 BOM递归方法整理

2013年04月15日 ⁄ 综合 ⁄ 共 2483字 ⁄ 字号 评论关闭

/*----------------------------------------------
标题:SQL2005 BOM递归方法整理
(以公司组织架构为例)

整理人:htl258(Tony)

日期:2009.04.25(引用请保留此信息)
------------------------------------------------*/
-->创建测试环境
DECLARE @t TABLE
(
FullDept
VARCHAR(20), --部门全称
Dept VARCHAR(20), --部门
ParentDept VARCHAR(20), --上级部门
Supervisor VARCHAR(20) --部门主管
)
INSERT @t SELECT 'S-IT' ,'IT','S' ,'Peter'
UNION ALL SELECT 'S-IT-CN' ,'CN','S-IT' ,'Mary'
UNION ALL SELECT 'S-IT-CN-SH' ,'SH','S-IT-CN' ,'Jack'
UNION ALL SELECT 'S-FS-AP' ,'AP','S-FS' ,'Colin'
UNION ALL SELECT 'S-FS' ,'FS','S' ,'Jerry'
UNION ALL SELECT 'S' ,'0' ,'0' ,'CiCi'
/*
SELECT * FROM @t
--------------------
FullDept(部门全称) Dept(部门) ParentDept(上级部门) Supervisor(部门主管)
-------------------- -------------------- -------------------- --------------------
S-IT IT S Peter
S-IT-CN CN S-IT Mary
S-IT-CN-SH SH S-IT-CN Jack
S-FS-AP AP S-FS Colin
S-FS FS S Jerry
S 0 0 CiCi
(6 行受影响)
*/
-->1.使用CTE递归返回指定根的子树查询:
--
->例1.查询部门主管为"Peter"的所有下级部门清单
;WITH t AS
(
SELECT *,0 as lvl /*展开层次*/ FROM @t WHERE Supervisor = 'Peter'
UNION ALL
SELECT a.*,b.lvl+1 FROM @t a /*原表*/ JOIN t b /*CTE*/ ON a.ParentDept = b.FullDept /*原表父项等于CTE子项*/
)
SELECT * FROM t ORDER BY FullDept;
/*
FullDept Dept ParentDept Supervisor lvl
-------------------- -------------------- -------------------- -------------------- -----------
S-IT IT S Peter 0
S-IT-CN CN S-IT Mary 1
S-IT-CN-SH SH S-IT-CN Jack 2

(3 行受影响)
*/
--->例2.查询部门主管为"Cici"的所有下级部门清单
;WITH t AS
(
SELECT *,0 as lvl /*展开层次*/ FROM @t WHERE Supervisor ='Cici'
UNION ALL
SELECT a.*,b.lvl+1 FROM @t a /*原表*/ JOIN t b /*CTE*/ ON a.ParentDept = b.FullDept /*原表父项等于CTE子项*/
)
SELECT * FROM t ORDER BY FullDept;
/*
FullDept Dept ParentDept Supervisor lvl
-------------------- -------------------- -------------------- -------------------- -----------
S 0 0 CiCi 0
S-FS FS S Jerry 1
S-FS-AP AP S-FS Colin 2
S-IT IT S Peter 1
S-IT-CN CN S-IT Mary 2
S-IT-CN-SH SH S-IT-CN Jack 3

(6 行受影响)
*/
-->2.使用CTE递归返回指定子项的父项查询:
--
->例1.查询部门主管为"Jack"的所有上级部门清单
;WITH t AS
(
SELECT *,0 as lvl /*展开层次*/ FROM @t WHERE Supervisor = 'Jack'
UNION ALL
SELECT a.*,b.lvl+1 FROM @t a /*原表*/ JOIN t b /*CTE*/ ON b.ParentDept = a.FullDept /*CTE父项等于原表子项*/
)
SELECT * FROM t ORDER BY FullDept;
/*
FullDept Dept ParentDept Supervisor lvl
-------------------- -------------------- -------------------- -------------------- -----------
S 0 0 CiCi 3
S-IT IT S Peter 2
S-IT-CN CN S-IT Mary 1
S-IT-CN-SH SH S-IT-CN Jack 0

(4 行受影响)
*/
--->例2.查询部门主管为"Colin"的所有上级部门清单
;WITH t AS
(
SELECT *,0 as lvl /*展开层次*/ FROM @t WHERE Supervisor = 'Colin'
UNION ALL
SELECT a.*,b.lvl+1 FROM @t a /*原表*/ JOIN t b /*CTE*/ ON b.ParentDept = a.FullDept /*CTE父项等于原表子项*/
)
SELECT * FROM t ORDER BY FullDept;
/*
FullDept Dept ParentDept Supervisor lvl
-------------------- -------------------- -------------------- -------------------- -----------
S 0 0 CiCi 2
S-FS FS S Jerry 1
S-FS-AP AP S-FS Colin 0

(3 行受影响)
*/

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