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如何判断全角半角

2012年07月11日 ⁄ 综合 ⁄ 共 1940字 ⁄ 字号 评论关闭

int IsChineseOrEnglish(LPCSTR pText)
{
 unsigned char sqChar[10];
 sqChar[0]=*pText;
 sqChar[1]='/0';
 if (sqChar[0]>=0xa1)
 {
  if (sqChar[0]==0xa3)
  {
   return 1;//全角字符  }
  else
  {
   return 2;//汉字  }
 }
 else
 {
  return 0;//英文,英文标点,数字

 }
}
bool GetNumChineseAndNumEnglish(const char*pSrc, int &nNumChiRet, int &nNumEngRet)//获得汉字与英文的个数
{
 if (pSrc == NULL)
 {
  return false;
 }
 else
 {
  int nLen = strlen(pSrc);
  char *pTxt = new char[nLen +1];
  char *pHeader = pTxt;
  //LPCSTR pTxt = pSrc;
  strcpy(pTxt, pSrc);
  pTxt[nLen] = '/0';
  while (*pTxt != '/0')
  {
   int nRet = IsChineseOrEnglish(pTxt);
   switch (nRet)
   {
   case 0:
    ++ nNumEngRet;
    pTxt++;
    break;
   case 1:
   case 2:
    ++ nNumChiRet;
    pTxt++;
    pTxt++;
    break;
   default:
    break;
   }
   
  }
  if (pHeader != NULL)
  {
   delete [] pHeader;
   pHeader = NULL;
  }
  return true;
 }
}

下面是完整的测试程序:

#include <windows.h>  
#include <iostream>
using namespace std;
int IsChineseOrEnglish(LPCSTR pText);
bool GetNumChineseAndNumEnglish(const char*pSrc, int &nNumChiRet, int &nNumEngRet);ÎĵÄ×Ö·û¸öÊý
int main(int argc,char**argv)  
{  

 int nNumChin = 0;
 int nNumEng = 0;
 GetNumChineseAndNumEnglish("£áÑîСӱYanger7", nNumChin, nNumEng);
 cout << "Number of Chinese:" << nNumChin << endl;
 cout << "Number of English:" << nNumEng << endl;
 return 0;  
}  

int IsChineseOrEnglish(LPCSTR pText)
{
 unsigned char sqChar[10];
 sqChar[0]=*pText;
 sqChar[1]='/0';
 if (sqChar[0]>=0xa1)
 {
  if (sqChar[0]==0xa3)
  {
   return 1;  }
  else
  {
   return 2;//ºº×Ö
  }
 }
 else
 {
  return 0; }
}
bool GetNumChineseAndNumEnglish(const char*pSrc, int &nNumChiRet, int &nNumEngRet){
 if (pSrc == NULL)
 {
  return false;
 }
 else
 {
  int nLen = strlen(pSrc);
  char *pTxt = new char[nLen +1];
  char *pHeader = pTxt;
  //LPCSTR pTxt = pSrc;
  strcpy(pTxt, pSrc);
  pTxt[nLen] = '/0';
  while (*pTxt != '/0')
  {
   int nRet = IsChineseOrEnglish(pTxt);
   switch (nRet)
   {
   case 0:
    ++ nNumEngRet;
    pTxt++;
    break;
   case 1:
   case 2:
    ++ nNumChiRet;
    pTxt++;
    pTxt++;
    break;
   default:
    break;
   }
   
  }
  if (pHeader != NULL)
  {
   delete [] pHeader;
   pHeader = NULL;
  }
  return true;
 }
}

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