//无比之水,按照题目要求做就行,求面积时,把面积之和后,在除2,避免精度缺失。 #include<stdio.h> #include<string.h> #include<algorithm> #include<math.h> #include<queue> #define dist(a,b) sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y)) #define cross(a,b,c) (b.x-a.x)*(c.y-a.y)-(b.y-a.y)*(c.x-a.x) #define dot(a,b,c) (b.x-a.x)*(c.x-a.x)+(b.y-a.y)*(c.y-a.y) #define delt(a) fabs(a)<eps?0:a>0?1:-1 #define pi acos(-1.0) #define eps 1e-8 #define inf 1e20 #define N 1000005 #define M 1005 using namespace std; typedef __int64 i64; struct TPoint { int x,y; }a,b,c; int n; int dir[10][2]={{0,0},{-1,-1},{0,-1},{1,-1},{-1,0},{0,0},{1,0},{-1,1},{0,1},{1,1}}; char str[N]; i64 sumf; int main() { scanf("%d",&n); while(n--) { scanf("%s",str); int len = strlen(str); int i,j,k; a.x=0,a.y=0; c.x=a.x+dir[str[0]-'0'][0]; c.y=a.y+dir[str[0]-'0'][1]; for(i=1,sumf=0;i<len;i++) { b=c; c.x=b.x+dir[str[i]-'0'][0]; c.y=b.y+dir[str[i]-'0'][1]; sumf+=cross(a,b,c); } if(sumf<0) sumf=-sumf; printf("%I64d",sumf/2); if(sumf&1) printf(".5"); puts(""); } return 0; }
【上篇】Syntax error,parameterized types are only available if source level is 5.0
【下篇】March 22th Monday 2010
【下篇】March 22th Monday 2010