//a^b循环节为4
#include <iostream> #include <cmath> using namespace std; int cal(int a,int b) { a = a%10; if( b >= 1 && b <= 4) return ((int)pow((float)a,(float)b))%10; else if(b > 4) return cal(a,b%4); else if(b == 0) return cal(a,4); } int A,B; int main() { while(cin>>A>>B) { cout<<cal(A,B)<<endl; } return 0; }