获取当前访问URI并保存于session中:
String uri = request.getRequestURI(); String param = ""; try { if(request.getQueryString() != null) { param = new String(request.getQueryString().getBytes("ISO8859-1"),"UTF-8"); } } catch (UnsupportedEncodingException e) { e.printStackTrace(); } if(!param.equals("")) { uri += "?"+param; } session.put("uri", uri);
当登录失败时跳转到失败页面,当登录成功时跳转到当前访问的页面或者给予提示:
下面是struts2跳转提示页面代码
<%@page contentType="text/html;charset=utf-8"%> <%@ taglib uri="/struts-tags" prefix="s" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>跳转提示</title> <script type="text/javascript" src="/js/jquery-1.4.min.js"></script> <script type="text/javascript"> var second=3; $(function() { $("#secondSpan").text(second+""); var fuc = function(){ second-=1; $("#secondSpan").text(second+""); if(second==0) { location="${uri}"; }else{ setTimeout(fuc,1000); } }; fuc();//开始倒计时 }); </script> </head> <body> <div> <h2>${curUser.username }您已成功登陆!</h2> <h3> </h3> <h3>页面在<span id="secondSpan"></span>秒后将重新转回 <a href="${uri}"></a>。如果转入失败,请单击<a href="${uri}">这里</a>。</h3> </div> </body> </html>
在登录处理的servlet或者action中不要做记录,否则可能陷入循环。。