while(cin >> a)
{
if(a == 'E') break;
cin >> aa >> b >> bb;
memset(var,0,sizeof(var));
var[a] = aa;
var[b] = bb;
T = H = D = 0;//注意初始化
if(var['T'] != 0) T = var['T'];
if(var['D'] != 0) D = var['D'];
if(var['H'] != 0) H = var['H'];//通过这种形式赋值可以简化判断结构
if(T != 0 && D != 0)
{
e = 6.11 * pow(Exp,5417.7530 * ((1/273.16) - (1/(D+273.16))));
h = (0.5555) * (e - 10.0);
H = T + h;
print();
}
else if(T != 0 && H != 0)
{
h = H - T;
e = h / 0.5555 + 10.0;
D = 1/(log(e/6.11)/((-1)*5417.7530) + 1/273.16) - 273.16;
print();
}
else if(H != 0 && D != 0)
{
e = 6.11 * pow(Exp,5417.7530 * ((1/273.16) - (1/(D+273.16))));
h = (0.5555) * (e - 10.0);
T = H - h;
print();
}
}
return 0;
}