用1,2,3,...,9组成3个三位数abc,def和ghi,每个数字恰好使用一次,要求abc:def:ghi=1:2:3。输出所有解。
#include <stdlib.h> #include <stdio.h> #include <string.h> int a[9] = {1, 2, 3, 4, 5, 6, 7, 8, 9}; char found = 0; void swap(int *a, int *b) { int temp; temp = *a; *a = *b; *b = temp; } void getNum(int begin, int n) { int i, first, second, third; if (found) { return; } if (begin >= n) { first = a[0]*100+a[1]*10+a[2]; second = a[3]*100+a[4]*10+a[5]; third = a[6]*100+a[7]*10+a[8]; if ((2*first == second) && (3*first == third)) { printf("first = %d\n", first); printf("second = %d\n", second); printf("third = %d\n", third); found = 1; return; } } else { for (i = begin; i < n; i++) { swap(&a[begin], &a[i]); getNum(begin+1, n); swap(&a[begin], &a[i]); } } } int main() { getNum(0, 9); return 0; }