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判断一个点是否落在多边形内

2013年09月10日 ⁄ 综合 ⁄ 共 2934字 ⁄ 字号 评论关闭

转自:

http://www.cnblogs.com/gis_gps/archive/2009/02/12/1389071.html

备用

一、背景:

  如何判断一个指定的经纬度点是否落在一个多边形区域内?

二、实现代码(delphi)

复制代码


Type

  TMyPoint
=
packed
record

    X : double;

    Y : double;

 
end;

{*------------------------------------------------------------------------------

  判断指定的经纬度坐标点是否落在指定的多边形区域内

  @param ALon   指定点的经度

  @param ALat   指定点的纬度

  @param APoints   指定多边形区域各个节点坐标

  @return True 落在范围内 False 不在范围内

------------------------------------------------------------------------------*
}
function IsPtInPoly(ALon, ALat: double; APoints:
array
of TMyPoint): Boolean;
var

  iSum, iCount, iIndex: Integer;

  dLon1, dLon2, dLat1, dLat2, dLon: double;
begin

  Result :
= False;

 
if (Length(APoints)
<
3)
then

 
begin

    Result :
= False;

    Exit;

 
end;

  iSum :
=
0;

  iCount :
= Length(APoints);

 
for iIndex :=0
to iCount
-
1
do

 
begin

   
if (iIndex
= iCount
-
1)
then

   
begin

      dLon1 :
= APoints[iIndex].X;

      dLat1 :
= APoints[iIndex].Y;

      dLon2 :
= APoints[0].X;

      dLat2 :
= APoints[0].Y;

   
end

   
else

   
begin

      dLon1 :
= APoints[iIndex].X;

      dLat1 :
= APoints[iIndex].Y;

      dLon2 :
= APoints[iIndex
+
1].X;

      dLat2 :
= APoints[iIndex
+
1].Y;

   
end;

   
if ((ALat
>= dLat1)
and (ALat
< dLat2))
or ((ALat>=dLat2)
and (ALat
< dLat1))
then

   
begin

     
if (abs(dLat1
- dLat2)
>
0)
then

     
begin

        dLon :
= dLon1
- ((dLon1
-dLon2)
* (dLat1
-ALat))
/ (dLat1
- dLat2);

       
if (dLon
< ALon)
then

          Inc(iSum);

     
end;

   
end;


 
end;

 
if (iSum
mod
2
<>
0)
then

    Result :
= True;
end;

复制代码

____________________________________________________________________________________________________________________________

C#算法

/// <summary>
        ///  判断指定的经纬度坐标点是否落在指定的多边形区域内
        /// </summary>
        /// <param name="ALon">指定点的经度</param>
        /// <param name="ALat">指定点的纬度</param>
        /// <param name="APoints">指定多边形区域各个节点坐标</param>
        /// <returns>True 落在范围内 False 不在范围内</returns>
        public bool isPtInPoly(double ALon, double ALat, Point[] APoints)
        {
            int iSum, iCount, iIndex;
            double dLon1, dLon2, dLat1, dLat2, dLon;
            if (APoints.Length < 3)
            {
                return false;
            }
            iSum = 0;
            iCount = APoints.Length;
            for (iIndex = 0; iIndex < iCount - 1; iIndex++)
            {
                if (iIndex == iCount - 1)
                {
                    dLon1 = APoints[iIndex].X;
                    dLat1 = APoints[iIndex].Y;
                    dLon2 = APoints[0].X;
                    dLat2 = APoints[0].Y;
                }
                else
                {
                    dLon1 = APoints[iIndex].X;
                    dLat1 = APoints[iIndex].Y;
                    dLon2 = APoints[iIndex + 1].X;
                    dLat2 = APoints[iIndex + 1].Y;
                }
                if (((ALat >= dLat1) && (ALat < dLat2)) || ((ALat >= dLat2) && (ALat < dLat1)))
                {
                    if (Math.Abs(dLat1 - dLat2) > 0)
                    {
                        dLon = dLon1 - ((dLon1 - dLon2) * (dLat1 - ALat)) / (dLat1 - dLat2);
                        if (dLon < ALon)
                            iSum++;
                    }
                }

            }
            if ((iSum % 2) != 0)
                return true;
            return false;
        }

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