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POJ4044 A Score Sequence

2013年09月11日 ⁄ 综合 ⁄ 共 948字 ⁄ 字号 评论关闭
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
int cmp(const int &a , const int &b)
{
    return a >= b;
}
int cmp1(const int &a , const int &b)
{
    if(a%10 == b%10)
    {
        return a <= b;
    }
    else
    {
        return a%10 <= b%10;
    }
}
int m, n, n1[35], n2[35], dp[35], res[35];
int main()
{
    int t;
    cin >> t;
    while(t--)
    {
        cin >> m >> n;
        for(int i = 0 ; i < m ; i++) cin >> n1[i];
        for(int i = 0 ; i < n ; i++) cin >> n2[i];
        sort(n1,n1+m,cmp);
        sort(n2,n2+n,cmp);
        memset(dp,0,sizeof(dp));
        int p1, p2, dppos = 0;
        p1 = p2 = 0;
        while(p1 < m && p2 < n)
        {
            if(n1[p1] == n2[p2])
            {
                p1++;
                p2++;
                dp[dppos]++;
            }
            else if(n1[p1] > n2[p2])
            {
                p1++;
                dppos = p1;
            }
            else
            {
                p2++;
            }
        }
        int index , maxlen;
        maxlen = 0;
        for(int i = 0 ; i < min(m,n) ; i++)
        {
            if(dp[i] > maxlen)
            {
                index = i;
                maxlen = dp[i];
            }
        }
        if(maxlen == 0)
        {
            printf("NONE\n");
            continue;
        }
        else
        {
            int pos = 0;
            for(int i = index ; i < index+maxlen ; i++)
            {
                if(i == 0) res[pos++] = n1[i];
                else
                {
                    //重复不记
                    if(n1[i] != n1[i-1]) res[pos++] = n1[i];
                }
            }
            for(int i = 0 ; i <= pos-1 ; i++)
                printf("%d ",res[i]);
                printf("\n");
            sort(res,res+pos,cmp1);
            for(int i = 0 ; i <= pos-1 ; i++)
                printf("%d ",res[i]);
                printf("\n");
        }
    }
    return 0;
}

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