今天听课的时候突然提到一个问题,如何把链表逆序,考虑一下,简单指针操作即可。
#include<iostream> using namespace std; struct node { int data; node* next; }; class LinkedList { public: LinkedList() { first = new node; int i = 1; node* p = first; while(i < 10) { node* q = new node; q->data = i; q->next = NULL; p->next = q; p = p->next; i++; } }; void putOut() { node* p = first->next; while(p != NULL) { cout << p->data << endl; p = p->next; } }; void reverse() { node* p = NULL; node* q = first->next; while(q != NULL){ node *m = q->next; q->next = p; if(m == NULL) { first->next = q; break; } else { p = q; q = m; } } } private: node* first; }; int main() { LinkedList a; a.putOut(); a.reverse(); a.putOut(); return 0; }