大意略。
思路:将经纬度转换为空间坐标,求解即可。
#include <iostream>
#include <cstdlib>
#include <cstdio>
#include <string>
#include <cstring>
#include <cmath>
#include <vector>
#include <queue>
#include <stack>
#include <algorithm>
using namespace std;
const double R = 6371009.0;
const double PI = acos(-1);
struct Point
{
double x, y, z;
Point(double x = 0, double y = 0, double z = 0): x(x), y(y), z(z) {};......
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