学步园

K Smallest Sums

You're given k arrays, each array has k integers. There are k^k ways to pick exactly one element in each array and calculate the sum of the integers. Your task is to find the k smallest sums among them.

Input

There will be several test cases. The first line of each case contains an integer k (2<=k<=750). Each of the following k lines contains k positive integers in each array. Each of these integers does not exceed 1,000,000. The input is terminated by end-of-file
(EOF). The size of input file does not exceed 5MB.

Output

For each test case, print the k smallest sums, in ascending order.

Sample Input

3
1 8 5
9 2 5
10 7 6
2
1 1
1 2

Output for the Sample Input

9 10 12
2 2

#include<iostream>
#include<queue>
#include<algorithm>

using namespace std;

const int MAXN=1000;

struct Node{
	int s,b;
};

int B[MAXN];

bool operator <(Node a, Node b)
{
	return a.s>b.s?true:false;
}

priority_queue<Node> a,b;

int main()
{
	int i,j,k;
	Node tmp;

	while(cin>>k)
	{
		for(i=0;i<k;i++)
		{
			cin>>tmp.s;
			a.push(tmp);
		}
		for(i=1;i<k;i++)
		{
			for(j=0;j<k;j++)
				cin>>B[j];
			sort(B,B+k);
			while(!b.empty())
				b.pop();

			while(!a.empty())
			{
				tmp=a.top();	a.pop();
				tmp.b=0;		tmp.s+=B[0];
				b.push(tmp);
			}

			while(a.size()<k)
			{
				a.push(b.top());
				tmp=b.top();
				tmp.s=tmp.s-B[tmp.b]+B[tmp.b+1];
				tmp.b++;
				b.pop();
				b.push(tmp);
			}
		}

		while(!a.empty())
		{
			tmp=a.top();
			if(a.size()==1)
				cout<<tmp.s<<endl;
			else
				cout<<tmp.s<<' ';
			a.pop();
		}
	}

	return 0;
}