An Easy Task
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 14727 Accepted Submission(s): 9404
Problem Description
Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?
Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.
Note: if year Y is a leap year, then the 1st leap year is year Y.
Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.
Note: if year Y is a leap year, then the 1st leap year is year Y.
Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).
Each test case contains two positive integers Y and N(1<=N<=10000).
Output
For each test case, you should output the Nth leap year from year Y.
Sample Input
3 2005 25 1855 12 2004 10000
Sample Output
2108 1904 43236
题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=1076
/*
给定起始年 计算第N个闰年
*/
#include<iostream>
using namespace std;
int main(){
int m,n,y,i,k;
cin>>m;
while(m--)
{
cin>>y>>n;
k=0;
for(i=y;;i++)
{
if((i%4==0&&i%100!=0)||i%400==0) k++;
if (k==n)
{
printf("%d\n",i);
break;
}
}
}
return 0;
}