NPY is going to have a PE test.One of the test subjects is throwing the shot.The height of NPY is H meters.He can throw the shot at the speed of v0 m/s and at the height of exactly H meters.He wonders if he throws the shot at the
best angle,how far can he throw ?(The acceleration of gravity, g, is
9.8m/s2)

The first line contains a integer
T(T≤10000),which
indicates the number of test cases.
The next T lines,each contains 2 integers H(0≤h≤10000m),which
means the height of NPY,and v0(0≤v0≤10000m/s),
which means the initial velocity.

For each query,print a real number X that was rounded to 2 digits after decimal point in a separate line.X indicates the farthest distance he can throw.

2
0 1
1 2

0.10
0.99
Hint
If the height of NPY is 0,and he throws the shot at the 45° angle, he can throw farthest.
/*
HDU 5144 物理题，抛球距离最远 
*/
#include<iostream>
#include<stdio.h>
#include<math.h>
using  namespace std;
#define G 9.8
int main()
{
	int t,h,v;
	scanf("%d",&t);
	while(t--)
	{
		scanf("%d%d",&h,&v);		
		printf("%.2lf\n",1.0*v*(sqrt(v*v+2*G*h))/G);
	}
	return 0;
}